DATASHEET AN6884 PDF
AN datasheet, AN circuit, AN data sheet: PANASONIC – 5-Dot LED Driver Circuit,alldatasheet, datasheet, Datasheet search site for Electronic. AN datasheet, AN pdf, AN data sheet, datasheet, data sheet, pdf, Panasonic, 5-Dot LED Driver Circuit. Description, 5-dot Led Driver Circuit. Company, Panasonic Industrial Company/ Electronic Components. Datasheet, Download AN datasheet. Cross ref.
|Published (Last):||17 December 2013|
|PDF File Size:||13.39 Mb|
|ePub File Size:||9.65 Mb|
|Price:||Free* [*Free Regsitration Required]|
There’s still a much an6848 range over which a varying number of LEDs come on. Most people use “low” to refer to either a lower voltage, or a lower position on the diagram. It sounds like you’re trying to drive this circuit with a signal that includes a considerable DC bias, which explains why all of the LEDs light up right away when you remove short out the capacitor.
There is also no discharge path with your arrangement. I’m not reading it that way.
AN Datasheet(PDF) – Panasonic Semiconductor
As displayed, the LEDs go from fully off to fully on over roughly the entire turn range of the potentiometer.
Setting 7 higher than ground biases the low side of the comparators, allowing them to turn on with a lower output from the amp. I’m not following you. The potentiometer is clear, but dwtasheet 2. You should fix the capitalisation of sentences and electrical units ‘F’ for farad to improve legibility and credibility.
The diode will mess up the response of the chip due to its forward voltage drop. Have you tried a non-polarized capacitor e. That is to say that the LEDs all come on at a much smaller turn of the potentiometer. Pin 8 accepts a positive input voltage.
Sign up using Facebook. Per AN’d datasheetPin 8 is the signal input pin, and it’s the internal Op amp’s positive input.
(PDF) AN6884 Datasheet download
By “low side”, you’re referring to the inverting inputs of the comparators. Your description doesn’t agree with that in the datasheet.
Very confusing terminology, since the inverting input can have a higher voltage than the noninverting input. It’s the DC bias determine the polarity. To be clear, removing the capacitor doesn’t light up the LEDs all at once. You might want to edit to explain your answer a bit more. I know the correct names, but I conversely find “inverting” and “noninverting” confusing when dealing with comparators, since those terms make more sense when dealing with op-amps.
Can someone explain what the reversed capacitor is doing here? Email Required, but never shown. However, if that’s the case, I can’t explain why reversing the capacitor doesn’t work, unless the actual polarity of the capacitor is backwards from what you think it is. If I remove the 2. Reverse biased capacitor on IC input pin Ask Question.
How does doing anything to pin 7 or pin 8 affect that?
Home Questions Tags Users Unanswered. That’s clear, because the input in my test circuit is DC. Right, I get that pin 7 is the output of the amp, but it’s part of the negative feedback loop on the amp.